4x^2-10=198

Solution for 4x^2-10=198 equation:

4x^2-10=198

We move all terms to the left:

4x^2-10-(198)=0

We add all the numbers together, and all the variables

4x^2-208=0

a = 4; b = 0; c = -208;
Δ = b2-4ac
Δ = 02-4·4·(-208)
Δ = 3328
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{3328}=\sqrt{256*13}=\sqrt{256}*\sqrt{13}=16\sqrt{13}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-16\sqrt{13}}{2*4}=\frac{0-16\sqrt{13}}{8}
=-\frac{16\sqrt{13}}{8}
=-2\sqrt{13}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+16\sqrt{13}}{2*4}=\frac{0+16\sqrt{13}}{8}
=\frac{16\sqrt{13}}{8}
=2\sqrt{13}
$